Question

If 9\geq4x+19≥4x+19, is greater than or equal to, 4, x, plus, 1, which inequality represents the possible range of values of 12x+312x+312, x, plus, 3?

Answer 1

`12x+3\leq 27`

Explanation:

It is given that

`9\geq4x+1`

We need to find the possible range of values of 12x+3.

Subtract -1 from both sides.

`9-1\geq 4x`

`8\geq 4x`

Multiply both sides by 3.

`24\geq 12x`

Add 3 on both sides.

`24+3\geq 12x+3`

`27\geq 12x+3`

It can be rewritten as

`12x+3\leq 27`

Therefore, 12x+3 must be less than or equal to 27.