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The sum of two numbers is 27. One number is 2 times as large as the other. What are the numbers?

2 Answers

5 votes

Answer:

9 and 18

Explanation:

let the numbers be x and 2x

so that x+2x=27

3x=27

x=9

so the numbers are 9 and 18.

I hope this will help

User Colin Cochrane
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4 votes

Answer:

  • 9 and 18


\\

Explanation:

It is given that, the sum of two numbers is 27 and one of the number is 2 times as large as the other.


\\

Let us assume the one number as x and as state in the question, one of the number is 2 times as large as the other (x) . So, the other number will be 2x .


\\

Now,


\\ {\longrightarrow \pmb{\sf {\qquad x + 2x = 27 \:}}} \\ \\

Adding like terms we get :


\\ {\longrightarrow \pmb{\sf {\qquad 3x = 27 \:}}} \\ \\

Dividing both sides by 3 we get :


\\ {\longrightarrow \pmb{\sf {\qquad (3x)/(3) = (27)/(3) \:}}} \\ \\


{\longrightarrow \pmb{\frak {\qquad {x} = {9} \:}}} \\ \\

So,

  • One of the number is 9.


\\

Now,


\\ {\longrightarrow \pmb{\frak {\qquad Other \: number = 2x \:}}} \\ \\


{\longrightarrow \pmb{\frak {\qquad Other \: number = 2(9) \:}}} \\ \\


{\longrightarrow \pmb{\frak {\qquad Other \: number = 18 \:}}} \\ \\

Therefore,

  • The two numbers are 9 and 18.
User Willy
by
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