Question

A trapeze artist, with swing, weighs 800 N; he is momentarily held to one side by his partner so that the swing ropes make an angle of 30.0 with the vertical. In such a condition of static equilibrium, what is the horizontal force being applied by the partner?

Answer 1

461.88 N

Step-by-step explanation:

The swing is in static equilibrium. T is the tension in the string. Refer to the attached figure.

In the vertical direction:

`T cos 30^o= mg = 800 N\\ \Rightarrow T = 923.76 N`

In the horizontal direction:

`F= T sin 30^o\\ \Rightarrow F = (923.76 * sin 30^o) N=461.88 N`

Thus, the horizontal force being applied by the partner is 461.88 N.