Question

7. Two children of mass 20 kg and 30 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the children are separated by a distance of 3 m, at what distance from the pivot point is the small child sitting in order to maintain the balance?

Answer 1

Step-by-step explanation:

Given

mass of children
`m_1=20\ kg`

`m_2=30\ kg`

distance between two children
`L=3\ m`

suppose small child is at a distance of x m from pivot point

so torque of small child and heavier child must be equal

`20* (x)=30* (3-x)`

`2x=9-3x`

`5x=9`

`x=1.8\ m`