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How to find the perimeter of A(−5,−1),B(−1,−1),C(−1,−4),D(−5,−4)

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Answer:

The perimeter of ABCD will be 14 units.

Explanation:

Points A(-5,-1) and B(-1,-1) lies on the same line which is parallel to the x-axis.

So, length of line segment AB will be |- 5 - (- 1)| = 4 units.

Points B(-1,-1) and C(-1,-4) lies on the line which is parallel to the y-axis.

So, length of line segment BC will be |- 4 - (- 1)| = 3 units.

Points C(-1,-4) and D(-5,-4) lies on the same line which is parallel to the x-axis.

So, length of line segment CD will be |- 5 - (- 1)| = 4 units.

Points D(-5,-4) and A(-5,-1) lies on the line which is parallel to the y-axis.

So, length of line segment DA will be |- 4 - (- 1)| = 3 units.

Therefore, the perimeter of ABCD will be (4 + 3 + 4 + 3) = 14 units. (Answer)

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