140k views
4 votes
ATP labeled with 32P a radioactive isotope of phosphorus at the gamma phosphate is added to a crude extract of a tissue rich in the enzymes of glycolysis along with glucose. What is the first intermediate of glycolysis that will no longer be radioactive?

User TheJosh
by
7.7k points

1 Answer

2 votes

Answer:

Piruvate

Step-by-step explanation:

Glucose + ATP32 --------> Glucose-6-P32 ----->Fructose-6-P32

Fructose-6-P32 + ATP32 ---------> Fructose-1,6 bi-P32

Fructose-1,6 bi-P32 ----------> Glyceraldehyde-3-P32 + Dihydroxiacetone Phosphate32 (that are in equilibrium)

Glyceraldehyde-3-P32 +NADH +Pi (non radioactive) -----> Glyceraldehyde-1,3-P32 (1,3 biphosphoglycerate where only in C3, there is a P32)

After that, the phosphorus in Carbon1 is donated to ADP to for ATP (non radioactive), and we have 3-Phosphoglycerate (radioactive because its P32), then it's converted to 2-Phosphoglycerate (radioactive), then Phosphoenolpiruvate (radioactive), that donates its P32 to ADP to produce ATP, remaining Piruvate as end product at the end of glucolysis

User Qballer
by
7.6k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.