Answer: p = - {1/2} , q = {1/2}
Explanation: The frequency of oscillation of a pendulum is given as
F = 1/2π *√{l/g}
Where √ is square root
l is lenght
g is acceleration due to gravity
But
F = 1/T
Where T is the period of Oscillation
Making T subject of formula we have
T= 1/F
T = 2π√{g/l}
Here the power on l is -[1/2]= p
Also,
Power on g is 1/2 =q
All because of the square root.