Question

The point-slope form of the equation of the line that passes through (–5, –1) and (10, –7) is y plus 7 equals negative StartFraction 2 over 5 EndFraction left-parenthesis x minus 10 right-parenthesis.. What is the standard form of the equation for this line?

Answer 1

2x + 5y = - 15

Explanation:

The line that passes through (–5, –1) and (10, –7) points and the point-slope form of the equation is
`y + 7 = - (2)/(5)(x - 10)`.

Now, we have to arrange this in the standard form.

So,
`y + 7 = - (2)/(5)(x - 10)`

⇒ 5(y + 7) = - 2(x - 10)

⇒ 5y + 35 = - 2x + 20

⇒ 2x + 5y = - 15 (Answer)