Question

What is the mass of 5.43x1045 molecules of Beo

Answer 1

The mass of 5.43x10^45 molecules of BeO can be calculated using the atomic masses provided in Appendix A.

Step-by-step explanation:

The mass of 5.43x10^45 molecules of BeO can be calculated using the atomic masses provided in Appendix A. The atomic mass of BeO is given by the formula BE = {[2m(^1H) + 2mn] - m(ª X)}c². We can substitute the atomic masses of ^1H (1.007825 u) and mn (1.008665 u) into the formula to calculate the binding energy (BE). By rearranging the formula, we can solve for the mass of 5.43x10^45 molecules of BeO.

Answer 2

2.255 x 10²³ g

Step-by-step explanation:

Data Given:

no. of molecules of BeO = 5.43 x 10⁴⁵ molecules

mass of BeO = ?

Solution:

first we will find no. of moles

Formula used

no. of moles = no. of molecules / Avogadro's number

Where

Avogadro's number = 6.022 x 10²³

Put values in above equation

no. of moles = 5.43 x 10⁴⁵ molecules / 6.022 x 10²³ (molecules/mol)

no. of moles = 9.02 x 10²¹ mol

So,

There are 9.02 x 10²¹ moles of BeO of 5.43x10⁴⁵

Now we will find the mass

For this formula will be used

No. of moles = Mass in grams/ molar mass

Rearrange the above equation

mass in grams = no. of moles x molar mass . . . . . (1)

molar mass of BeO = 9 + 16 = 25 g/mol

Put values in equation 1

mass in grams = 9.02 x 10²¹ moles x 25 g/mol

mass in grams = 2.255 x 10²³ g

So,

Mass of 5.43 x 10⁴⁵ molecules of BeO = 2.255 x 10²³ g