Answer:
a) 0.759 m , 0.759 m
b) 10.1 m , 10.3 m
c) 12.3 m , 13 m
Step-by-step explanation:
Vapour Pressure included:
![P_(atm,vp) = y*h + P_(vp) \\\\h = (P_(atm,vp)-P_(vp))/(y) ... Eq1](https://img.qammunity.org/2021/formulas/engineering/college/tdh8p2sepvkr2yttcv81bjsst7m5evbl9f.png)
mercury
![h_(Hg,vp) = (101*10^3-1.6*10^(-1))/(133*10^3) \\\\h_(Hg,vp) = 0.759m](https://img.qammunity.org/2021/formulas/engineering/college/y0ces1lguragfd99sjtdp4tws13okavhw4.png)
![h_(Hg) = (101*10^3)/(133*10^3) \\\\h_(Hg) = 0.759m](https://img.qammunity.org/2021/formulas/engineering/college/7vypud2qq960voll18ekyga3mtgvqn6s6r.png)
water
![h_(H2O,vp) = (101*10^3-1.77*10^3)/(9.8*10^3) \\\\h_(H2O,vp) = 10.1m](https://img.qammunity.org/2021/formulas/engineering/college/9cwt93lbns1tu7d74a68fdnynntfsrplpu.png)
![h_(H2O) = (101*10^3)/(9.8*10^3) \\\\h_(H20) = 10.3m](https://img.qammunity.org/2021/formulas/engineering/college/kuay0i5r0n1myp4fpg5svgdkxu9r24c56j.png)
Ethyl Alcohol
![h_(EA,vp) = (101*10^3-5.9*10^3)/(7.74*10^3) \\\\h_(EA,vp) = 12.3m](https://img.qammunity.org/2021/formulas/engineering/college/uf00am7owmibna0i7y3eb2rc4xy87a0wbc.png)
![h_(EA) = (101*10^3-5)/(7.74*10^3) \\\\h_(EA) = 13m](https://img.qammunity.org/2021/formulas/engineering/college/7qdd5si7gv27wl5f0jr5yubmx29fvwuext.png)
For mercury barometers the effects of vapour pressure are negligible and required height for mercury barometer is reasonable as compared to that of water and ethyl alcohol.