218k views
4 votes
Write a one sentence explanation for the following statement:

The presence in liver of glucose-6-phosphatase is essential to the function of the liver in synthesizing glucose for use by other tissues.
a. Glucose-6-phosphate must be hydrolyzed in order for glucose to exit the liver cell and be exported to other tissues.
b. Glucose-6-phosphate must be fully ucleaved in order for glucose to exit the liver cell and be exported to other tissues.
c. Glucose-6-phosphate must lower the energy barier of desorption in order for glucose to exit the liver cell and be exported to other tissues.
d. Glucose-6-phosphate must be activated in order for glucose to exit the liver cell and be exported to other tissues.

User H S W
by
8.4k points

1 Answer

2 votes

Answer:

a. Glucose-6-phosphate must be hydrolyzed in order for glucose to exit the liver cell and be exported to other tissues

Step-by-step explanation:

Liver cells contain a membrane bound enzyme called glucose-6-phosphatase for glycogenolysis by glucagon especially during starvation when free glucose is required. As glucagon enters the liver cells it activates the enzyme glucose-6-phosphatase which then acts on glucose-6-phosphate and hydrolyzes it. As glucose-6-phosphate is hydrolyzed, it results in the formation of a phosphate group and a free glucose. The free glucose thus formed is transported from the liver cell to other tissues by specific glucose transport membrane protiens.

User Russds
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.