Question

You wish to prepare 0.13 M HNO3 from a stock solution of nitric acid that is 16.6 M. How many milliliters of the stock solution do you require to make up 1.00 L of 0.13 M HNO3?

Answer 1

0.0078 L of the stock solution is required to make up 1.00 L of 0.13 M
`HNO_(3)`

Step-by-step explanation:

According to laws of equivalence,
`C_(1)V_(1)=C_(2)V_(2)`

where,
`C_(1)` and
`C_(2)` are initial and final concentration respectively.
`V_(1)` and
`V_(2)` are initial and final volume respectively.

Here,
`C_(1)=16.6M`,
`C_(2)=0.13M` and
`V_(2)=1.00L`

So,
`V_(1)=(C_(2)V_(2))/(C_(1))`

or,
`V_(1)=((0.13M)* (1.00L))/((16.6M))`

or,
`V_(1)=0.0078L`

Hence 0.0078 L of the stock solution is required to make up 1.00 L of 0.13 M
`HNO_(3)`