Answer:
n=0.03928 moles
Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles
Step-by-step explanation:
The amount of oxygen which lung can have is 20% of 5 L which is the capacity of lungs
Volume of oxygen in lungs =V=5*20%= 1 L=
![1*10^(-3) m^3](https://img.qammunity.org/2021/formulas/physics/college/n137qdfw8mkattw2l9plbgltot3ctzm1km.png)
Temperature=T=
![37^oC=273+37=310K](https://img.qammunity.org/2021/formulas/physics/college/4hahfub1b20875yvapd65h3jq05yju0g7b.png)
Pressure at sea level = P= 1 atm=
![1.0125*10^5 Pa](https://img.qammunity.org/2021/formulas/physics/college/ymoqe6gxvjfpu32ev6v12nb3adj3k6g5zb.png)
R is universal Gas Constant =8.314 J/mol.K
Formula:
![n=(PV)/(RT)\\n=((1.0125*10^5) *(1*10^(-3)))/((8.314)*310) \\n=0.03928 mol](https://img.qammunity.org/2021/formulas/physics/college/m6g60n4mt6l8okyk5atncmjgfzybnowoxr.png)
Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles