Question

In preparing to shoot an arrow, an archer pulls a bow string back 0.420 m by exerting a force that increases uniformly from 0 to 230 N. What is the equivalent spring constant of the bow? Answer in units of N/m.

Answer 1

spring constant will be 547.619 N /m

Step-by-step explanation:

We have given that force exerted if uniformly from 0 to 230 N

So exerted force F = 230 N

String is stretched by 0.420 m due to applying force

So x = 0.420 m

We have to find the spring constant in N/m

We know that stretched force is given by

`F=Kx` , here K is spring constant and x is stretched length

So
`230=K* 0.420`

`K=(230)/(0.420)=547.619N/m`

So spring constant will be 547.619 N /m