Question

A charge of 0.80nC is placed at the center of a cube that measures 4.0 m along each edge. What is the electric flux through one face of the cube?. 1. 5 N m2/C

2. 90 N m2/C
3. 45 N m2/C
4. 64 N m2/C
5. 23 N m2/C

Answer 1

Step-by-step explanation:

Given

Charge of
`Q=0.8\ nC`

Length of side of cube
`a=4\ m`

Total Flux through the cube
`\phi =(Q)/(\epsilon _0)`

`\epsilon _0=8.854* 10^(-12)\ C^2/N-m^2`

total Flux
`\phi=(0.8* 10^(-9))/(8.854* 10^(-12))`

`\phi =90.35\ N-m^2/C`

As cube has 6 faces , so flux through each face will be similar

thus flux through each face
`\phi'=(\phi )/(6)`

`\phi '=(90.35)/(6)=15\ N-m^2/C`