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What is the magnitude of the electric force of attraction between an iron nucleus (q=+26e) and its innermost electron if the distance between them is 1.5×10−12m?

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Final answer:

The magnitude of the electric force of attraction between an iron nucleus and its innermost electron can be calculated using Coulomb's law.

Step-by-step explanation:

The magnitude of the electric force of attraction between an iron nucleus and its innermost electron can be calculated using Coulomb's law. Coulomb's law states that the magnitude of the electric force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In this case, the charge of the iron nucleus (+26e) is given as 26 times the charge of an electron (e).

The formula to calculate the electric force is: F = k * |q1 * q2| / r^2, where F is the electric force, k is the electrostatic constant, q1 and q2 are the charges of the particles, and r is the distance between them.

Using this formula, we can plug in the values: F = (8.99 × 10^9 Nm^2/C^2) * |(26e) * (-e)| / (1.5 × 10^(-12)m)^2. Simplifying this equation will give you the magnitude of the electric force.

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