Answer:
1. Double displacement reaction
2. precipitation reaction.
Step-by-step explanation:
Part 1
Reaction Given:
CH₃COOH + NaHCO₃ -----> CO₂ + H₂O+ Na⁺ + CH3COO−
Reaction Type = ?
Solution:
In this reaction two reactant combine and give 3 products.
This reaction occur in two steps
In step one acetic acid react with sodium bicarbonate and gives sodium acetate plus carbonic acid.
CH₃COOH + NaHCO₃ -------> H₂CO₃ + CH3COONa
So, the above reaction is a double displacement reaction. where sodium of sodium carbonate replace hydrogen of acetic acid and vice versa.
In step two the cabonic acid decomposes in two components that is carbon dioxide and water.
H₂CO₃ -----------> CO₂ + H₂O
The overall reaction is
CH₃COOH + NaHCO₃ -----> CO₂ + H₂O + CH3COONa
As the CH3COONa exist in ions in solution so it can be written as
CH₃COOH + NaHCO₃ -----> CO₂ + H₂O + CH3COO⁻ Na⁺
So, the overall reaction is a double displacement reaction.
This is a double displacement reaction, in which Hydrogen (H) of the first compound replace the Sodium (Na) of the other compound.
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Part 2.
Reaction Given:
CaCl₂ + 2 NaHCO₃ -------→ CO₂ + CaCO₃ + 2 NaCl + H₂O
Solution
In this reaction two reactant combine and give 4 products.
Reactant of the reaction
CaCl₂ = calcium chloride
NaHCO₃ = sodium bicarbonate
Reactant of the reaction
CO₂= carbon dioxide
CaCO₃ = calcium carbonate
NaCl = sodium chloride
H₂O = water
So,
the reactant of the reaction that is calcium chloride react with sodium bicarbonate combine and form calcium carbonate and salt along with water and the evaluation of carbon dioxide.
As in this reaction calcium carbonate is formed in the form of precipitates so it is a precipitation reaction.
So
This is a type of precipitation reaction.