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If you start with 10.0 grams of lithium hydroxide and an excess of hydrogen bromide, how many grams of lithium bromide will be produced?

User Vicco
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1 Answer

3 votes

Answer:

grams of lithium bromide produced = 36.2642309286 ≈ 36.30 g

Step-by-step explanation:

The equation of the reaction is as follows ;

Lithium hydroxide + hydrogen bromide → Lithium Bromide + water

LiOH + HBr → LiBr + H2O

The equation is already balanced

Molecular mass of LiOH = 6.941 + 15.999 + 1.00784

Molecular mass of LiOH = 23.94784 g

Molecular mass of LiBr = 6.941 + 79.904 = 86.845 g

From the equation

LiOH + HBr → LiBr + H2O

23.94784 g of lithium hydroxide produces 86.845 g of lithium bromide

10 g of lithium hydroxide will produce ?

cross multiply

grams of lithium bromide produced = 10 × 86.845/23.94784

grams of lithium bromide produced = 868.45/23.94784

grams of lithium bromide produced = 36.2642309286 ≈ 36.30 g

User Kenesia
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