Question

Help with matrices please? Any wrong/not applicable answers will be reported and BLOCKED

Answer 1

m x H =
`\left[\begin{array}{ccc}-25&37.5&-12.5\\\9\end{array}\right]`

Explanation:

Step 1; Multiply 5 with this matrix
`\left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right]` and we get a matrix
`\left[\begin{array}{ccc}-5&10\\20&40\\\end{array}\right]`

Multiply the fraction
`(2)/(5)` with the matrix
`\left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right]` and we get
`\left[\begin{array}{ccc}-(2m)/(5) &(4m)/(5) \\(8m)/(5) &(16m)/(5) \\\end{array}\right]`

Step2; Now equate corresponding values of the matrices with each other.

-5 =
`(-2m)/(5)` and so on. By equating we get the value of m as
`(25)/(2)`

Step 3; Add the matrices to get the value of matrix m.

Adding the three matrices on the RHS we get
`\left[\begin{array}{ccc}2&9&-9\\\end{array}\right]`.

Step 4; Adding the matrices on the LHS we get the resulting matrix as H +

`\left[\begin{array}{ccc}4&6&-8\\\9\end{array}\right]`. Equating the matrices from step 3 and 4 we get the value of H as
`\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]`

Step 5; Now to find the value of m x H we need to multiply the value of
`(25)/(2)` with the matrix
`\left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]`

Step 6; Multiplying we get the matrix m x H = [ -25
`(75)/(2)`
`(-25)/(2)` ]