Question

A mixture of He and Ne need to be separated. What will be the ratio of the rates of effusion of He and Ne?

Answer 1

Ratio of rates of effusion of He to Ne is 2.245

Step-by-step explanation:

According to Graham's law rate of effusion is inversely proportional to square root of molar mass of a gas

So,
`(r_(He))/(r_(Ne))=\sqrt{(M_(Ne))/(M_(He))}`

where,
`r_(He)` and
`r_(Ne)` are rate of effusion of He and Ne respectively.
`M_(He)` and
`M_(Ne)` are molar mass of He and Ne respectively.

Molar mass of He = 4.003 g/mol

Molar mass of Ne = 20.18 g/mol

So,
`(r_(He))/(r_(Ne))=\sqrt{(20.18)/(4.003)}=2.245`

So, ratio of rates of effusion of He to Ne is 2.245