Question

Sodium permanganate and iron(III) chloride are both dissolved in a beaker of water. In a double displacement reaction, two new products are formed. a. Write the complete balanced chemical equation (using chemical formulas, not words) for this reaction. Include the physical states of the reactants and the products

Answer 1

The question involves writing a balanced chemical equation for a double displacement reaction between sodium permanganate and iron(III) chloride. Since iron(III) permanganate's solubility is not well-known, the expectancy of the reaction's products and progression is questionable, and further investigation on the actual reaction mechanism is needed.

Step-by-step explanation:

The subject of the question is a double displacement reaction between sodium permanganate and iron(III) chloride in water. According to the question, the likely products would be sodium chloride (NaCl) and iron(III) permanganate (Fe(MnO4)3), assuming iron(III) permanganate is not soluble. However, since iron(III) permanganate is not a common compound and its solubility is not well-known, it's possible that this reaction may not proceed as a typical double displacement reaction. Instead, iron may react with permanganate in a redox reaction, which is beyond the scope of the question. For educational purposes, the balanced equation for the proposed double displacement reaction would look like this:

3 NaMnO4(aq) + FeCl3(aq) → 3 NaCl(aq) + Fe(MnO4)3(s)

However, this is a hypothetical situation as the actual reaction may differ based on redox conditions and the actual solubility of the products formed.

Answer 2

Answer: The balanced chemical equation is written below.

Step-by-step explanation:

Double displacement reaction is defined as the reaction in which exchange of ions takes place.

`AB+CD\rightarrow CB+AD`

When sodium permanganate reacts with iron (III) chloride, it leads to the production of sodium chloride and iron (III) permanganate.

The chemical equation for the reaction of sodium permanganate and iron (III) chloride follows:

`3NaMnO_4(aq.)+FeCl_3(aq.)\rightarrow Fe(MnO_4)_3(s)+3NaCl(aq.)`

By Stoichiometry of the reaction:

3 moles of aqueous solution of sodium permanganate reacts with 1 mole of aqueous solution of iron (III) chloride to produce 1 mole of solid iron permanganate and 3 moles of aqueous solution of sodium chloride

Hence, the balanced chemical equation is written above.