Question

A small sphere with a mass of 441 g is moving upward along the vertical +y-axis when it encounters an electric field of 5.00 N/C . If, due to this field, the sphere suddenly acquires a horizontal acceleration of 13.0 m/s², what is the charge that it carries?A) 1.15 CB) -1.15 CC) 1150 CD) -1150 C

Answer 1

Answer: Option (A) is the correct answer.

Step-by-step explanation:

It is known that the relation between force and electric field is as follows.

F = qE .......... (1)

where, F = force

q = charge

E = electric field

Also, we know that, F = ma ...... (2)

Hence, equating equation (1) and (2) as follows.

qE = ma

or, q =
`(ma)/(E)`

Therefore, putting the given values into the above formula as follows.

q =
`(ma)/(E)`

=
`(441 g * 13.0 m/s^(2))/(5.0 N/C)`

= 1.1466 C

= 1.15 C (approx)

Therefore, we can conclude that the charge carried by given charge is 1.15 C.