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Solve by completing the square

Solve by completing the square-example-1

1 Answer

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Answer:

The answer is (-6 + √41), (-6 – √41)

Explanation:

We are given an equation

  • x² + 12x = 5

Subtract 5 from both side we get,

x² + 12x – 5 = 5 – 5

x² + 12x – 5 = 0

we get the equation in the form of

  • ax² + bx + c = 0

Here, a = 1, b = 12, c = (-5)

Now, Add and subtract (b/2a)² we get,

x² + 12x + (12/2)² – (12/2)² – 5 = 0

x² + 12x + (6)² – (6)² – 5 = 0

(x + 6)² – 36 – 5 = 0

(x + 6)² – 41 = 0

Now, add 41 both side we get,

(x + 6)² – 41 + 41 = 0 + 41

(x + 6)² = 41

√(x + 6)² = √41

x + 6 = ±√41

x = -6 + √41, -6 – √41

Thus, The roots of the equation is

(-6 + √41) and (-6 – √41).

-TheUnknownScientist 72

User Chendesheng
by
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