Question

A 1090 kg car moving +11.0 m/s

makes a head-on inelastic collision
with a stationary car. After, they
move +4.75 m/s. What is the
mass of the second car?​

Answer 1

1434.21 kg

Step-by-step explanation:

Answer 2

The mass of the second car is 1434.21 kg

Step-by-step explanation:

Using law of conservation of momentum,

`m_(1) u_(1)+m_(2) u_(2)=\left(m_(1)+m_(2)\right) v`

Given:

`m_(1)` = 1090 kg

`u_(1)` = 11 m/s

`u_(2)` = 0

v = 4.75 m/s

We need to find
`m_(2)`

When substituting the given values in the above equation, we get

`(1090 * 11)+\left(m_(2) * 0\right)=\left(1090+m_(2)\right) 4.75`

`11990=5177.5+4.75 m_(2)`

`4.75 m_(2)=11990-5177.5`

`4.75 m_(2)=6812.5`

`m_(2)=(6812.5)/(4.75)=1434.21 \mathrm{kg}`