Answer:
n=3m+5
n−2m=3
\hboxsubstitute3m+5forninthesecondequation:
3m+5−2m=3
m+5=3
m=3−5
m=−2
n=3×(−2)+5
n=−6+5
n=−1
(m,n)=(−2,−1)
The answer is C.
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