Question

A horse canters away from its trainer in a straight line, moving 126 m away in 13.0 s. It then turns abruptly and gallops halfway back in 5.0 s .Calculate: (a) its average speed? (b) its average velocity for the entire trip, using "away from the trainer" as the positive direction.

Answer 1

Answer.

given,

distance moved, d = 126 m

time = 13 s

then turns abruptly and gallops halfway back in 5.0 s .

a) Average speed = ?

total distance = 126 m + 62 m

= 189 m

total time = 13 + 5 = 18 s

`average\ speed = (total\ distance)/(total\ time)`

`average\ speed = (189)/(18)`

`average\ speed = 10.5 m/s`

b) average velocity of the entire trip

total displacement = 126 - 62 = 62 m

total time = 18 s

`average\ velocity = (total\ displacement)/(total\ time)`

`average\ velocity = (62)/(18)`

`average\ velocity = 3.44\ m/s`