Answer:
The answer to your question is below
Explanation:
See the picture below
Data
A (-2, 3)
B (4, 5)
I plotted the points C (4, 3) and D (-2, 5)
Distance
dAC =

=

= 6
dBD =

=

= 6
dAD =

=

= 2
dBC =

dBC =

dBC = 2
Total distance = dAC + dBD + dAD + dBC
Total distance = 6 + 6 + 2 + 2
= 16
I calculate the length of each side and then I sun them up.