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If g(x) = 3x - 4, what is the value of g-^1(g(13))?
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If g(x) = 3x - 4, what is the value of g-^1(g(13))?

User Fahim Bagar
by
3.6k points

1 Answer

1 vote
• g^-1

y = 3x – 4

3x = y + 4

x = y + 4 / 3

g^-1 = x + 4 / 3

• g(13)

3(13) – 4

39 – 4

g(13) = 35

• g^-1(g(13)) = (35) + 4 / 3

39 / 4

g^-1(g(13)) = 13
User Torvon
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