The distance between the points (1,2) and (x,-1) is 5 units. Find the possible values of x

asked Nov 16, 2023 230k views

12 votes

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10 votes

Answer:

-3,5

Explanation:

$d = \sqrt{(x _(2) - x _1) {}^(2) + (y _(2) - y _(1) {} ) {}^(2) }$

$5 = \sqrt{(x - 1) {}^(2) + ( - 1 - 2) {}^(2) }$

$5 = \sqrt{(x - 1) {}^(2) + ( - 3) {}^(2) }$

$25 = (x - 1) {}^(2) + 9$

$16 = (x - 1) {}^(2)$

4 = x - 1

x = 5

- 4 = x - 1

x = - 3

Jatin Gera answered Nov 20, 2023

3.5k points

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