Question

A veterinarian knows that a 50-pound dog gets 0.5 milligram of a certain medicine, and that the number of milligrams, m, varies directly with the weight of the dog, w. The vet uses these steps to find the amount of medicine to give a 10-pound dog. Step 1 Find the constant of variation. k = StartFraction 0.5 Over 50 EndFraction = 0.01 Step 2 Write the direct variation equation. m = 0.01 w Step 3 Substitute 10 into the equation to find the dosage for a 10-pound dog. 10 = 0.01 w Step 4 Solve for w. 10 = 0.01 w. W = 1000. The 10-pound dog needs 1000 milligrams. In which step did the veterinarian make the first error? Step 1 Step 2 Step 3 Step 4

Answer 1

step 3

Explanation:

Answer 2

Answer:the veterinarian made the first error in step 3

Explanation:

the number of milligrams, m, varies directly with the weight of the dog, w.

Assuming constant of variation is k, then,

m = kw

k = m/w = 0.5/50 = 0.01

Therefore,

m = 0.01w

In step 3, Substituting 10 into the equation to find the dosage for a 10-pound dog like 10 = 0.01w was error.

The correct step is

m = 0.01 × 10

m = 0.1 milligrams