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Factor the following quadratic expression completely : 64x^2
- 121

User Zhao
by
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2 Answers

2 votes

Answer:

Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) where a=8x and b=11

.

(8x+11)(8x−11)

Explanation:

User Wtekiela
by
4.0k points
2 votes

64x^2-121

Rewrite 64x^2 as 8x^2

Rewrite 121 as 11^2

Now you have 8x^2-11^2

Use the difference of squares formula, a^2- b^2 = (a+ b)( a-b) where a= 8x and b = 11

Answer is:

(8x+11)(8x-11)

User Osama AbuSitta
by
3.5k points