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Factorize: (2a+3b) the whole square-16c square
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5 votes
Factorize: (2a+3b) the whole square-16c square

User David Skarbrevik
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2 Answers

5 votes

Answer:

Explanation:

hello :

(2a+3b)² - (16c)² = [(2a+3b) - 16c]×[(2a+3b) + 16c]

= [2a + 3b - 16c]×[2a + 3b + 16c]

by identity : x²- y² = (x-y)(x+y) when x= 2a+3b and y = 16c

User Dmigo
by
6.5k points
2 votes

Answer:

(2a+3b)² - (16c)² = (2a + 3b - 16c)×(2a + 3b + 16c)

Explanation:

(2a+3b)² - (16c)² = [(2a+3b) - 16c]×[(2a+3b) + 16c]

= [2a + 3b - 16c]×[2a + 3b + 16c]

User Yzerman
by
5.7k points
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