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Factorize: (2a+3b) the whole square-16c square

asked Aug 14, 2021 11.6k views

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Dmigo · Answer 1 · 2021-08-14T22:16:46+0000

Answer:

Explanation:

hello :

(2a+3b)² - (16c)² = [(2a+3b) - 16c]×[(2a+3b) + 16c]

= [2a + 3b - 16c]×[2a + 3b + 16c]

by identity : x²- y² = (x-y)(x+y) when x= 2a+3b and y = 16c

Yzerman · Answer 2 · 2021-08-20T12:47:34+0000

Answer:

(2a+3b)² - (16c)² = (2a + 3b - 16c)×(2a + 3b + 16c)

Explanation:

(2a+3b)² - (16c)² = [(2a+3b) - 16c]×[(2a+3b) + 16c]

= [2a + 3b - 16c]×[2a + 3b + 16c]

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(2a+3b)² - (16c)² = (2a + 3b - 16c)×(2a + 3b + 16c)

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