233k views
1 vote
What are the domain and range of the function fix)=-3(x-5)2 +4?

1 Answer

1 vote

Answer:

domain of the function are x, 1, 2, 3 and range are 6x-26, -20, -14, -8

Explanation:

f(x)=3(x-5)2+4

=(3x-15)2+4

=6x-30+4

=6x-26

if the value of x is 1

f(1)=6×1-26

=-20

if value of x is 2

f(2)=6×2-26

=-14

if the value of x is 3

f(3)=6×3-26

=-8

User Zoran Pavlovic
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories