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What are the domain and range of the function fix)=-3(x-5)2 +4?

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Answer:

domain of the function are x, 1, 2, 3 and range are 6x-26, -20, -14, -8

Explanation:

f(x)=3(x-5)2+4

=(3x-15)2+4

=6x-30+4

=6x-26

if the value of x is 1

f(1)=6×1-26

=-20

if value of x is 2

f(2)=6×2-26

=-14

if the value of x is 3

f(3)=6×3-26

=-8

User Zoran Pavlovic
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