Question

In the nucleus of an atom, two protons are separated by a distance of 10^-13 m. What is the Coloumb force between them? The charge of a proton is + 1.602 x 10^-19 C.

Answer 1

`F=0.0231\ N`

Step-by-step explanation:

Electrostatic Force

When two point charges
`q_1` and
`q_2` are placed at a distance d, they exert a force to each other whose magnitude can be computed by the Coulomb's formula

`\displaystyle F=(k\ q_1\ q_2)/(d^2)`

Where k is the constant of proportionality

`k=9.10^9\ Nw.m^2/c^2`

The information provided is

`d=10^(-13)\ m`

`q_1=q_2=+ 1.602 x 10^(-19)\ C`

Computing the Coloumb force between them

`\displaystyle F=(9x10^9\ 1.602 x 10^(-19) \ 1.602 x 10^(-19) )/((10^(-13))^2)`

`\boxed{F=0.0231\ N}`