Answer:
a = 0
Explanation:
I find a graphing calculator useful for such questions. It shows the solution to be a = 0. For the graph, we have rewritten the equation from
(1/7)^(3a+3) = 343^(a-1)
to
(1/7)^(3x+3) -343^(x-1) = 0 . . . . . this graphing calculator likes x for the independent variable
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If you recognize that 343 is the cube of 7, you might solve this by taking logarithms to the base 7.
(7^-1)^(3a+3) = (7^3)^(a-1)
Equating exponents of 7*, we get ...
-(3a+3) = 3(a -1)
-3a -3 = 3a -3 . . . . . eliminate parentheses
0 = 6a . . . . . . . . . . . add 3+3a
0 = a . . . . . . . . . . . . divide by 6
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* Equating exponents of 7 is the same as taking logarithms to the base 7. Here, we use the rules of exponents ...
1/a^b = a^-b
(a^b)^c = a^(bc)