Answer:
![a=(b(zd-c))/(d)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pmxes54jlb1u4s2hrvkxsjviltum15oirh.png)
Explanation:
Having the following equation given in the exercise:
![z=(a)/(b)+(c)/(d)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7x0y2nlv04qs8fwg3djd9ru5yge2m6g8hh.png)
You can solve for "a" following this procedure:
1. You can apply the Subtraction property of equality and subtract
from both sides of the equation:
![z-((c)/(d))=(a)/(b)+(c)/(d)-((c)/(d))\\\\z-(c)/(d)=(a)/(b)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vteqjgq4g6q13sf8nb54xrudy856je0mlp.png)
2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:
![(zd-c)/(d)=(a)/(b)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5nizv9ac0vskm76dln20vl7ev2cs3buoea.png)
3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:
![(b)((zd-c)/(d))=((a)/(b))(b)\\\\a=(b(zd-c))/(d)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/dwud1v6ip3ct8ehsfxz0aeu408ds961coa.png)