The midpoint is

The distance between points S and T is 7.1 units
Solution:
Given points are S(−2, 4) and T(3, 9)
Find the coordinates of the midpoint of ST
The midpoint is given as:

Here in this sum,

Substituting the values, we get

Thus the midpoint is

Find the distance between points
The distance is given by formula:

Here in this sum,

Substituting the values, we get

Thus the distance between points S and T is 7.1 units