Answer:
59 in2
Explanation:
we know that
The area of the polygon is equal to the area of rectangle plus the area of two triangles
so
Find the area of rectangle
![A_1=LW](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xzm47k34blrrdzioulbbkb3kbb5evoc82z.png)
we have
![L=7\ in\\W=4\ in](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qzbwmkwde0zuit4d3evuycknrhm8qgeifd.png)
substitute
![A_1=(7)(4)=28\ in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2nxm2kyvcyx07pjmamq3m1be9llzsqe7qy.png)
Find the area of triangle with height of 6 in
![A=(1)/(2)bh](https://img.qammunity.org/2021/formulas/mathematics/high-school/pmi4atjsmn0794m9nb42tnma5o4ubiy66a.png)
we have
![b=7\ in\\h=6\ in](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2mlifvkh0mmxlnbx0sn4gyfyy0osi5ipx5.png)
substitute
![A_2=(1)/(2)(7)(6)=21\ in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lxziio43gwjtit04ox4r89i91lbfgf0ae0.png)
Find the area of triangle with height of 5 in
![A=(1)/(2)bh](https://img.qammunity.org/2021/formulas/mathematics/high-school/pmi4atjsmn0794m9nb42tnma5o4ubiy66a.png)
we have
![b=4\ in\\h=5\ in](https://img.qammunity.org/2021/formulas/mathematics/middle-school/des85vjftpe3arr1w2ep6inoypueb28khq.png)
substitute
![A_3=(1)/(2)(4)(5)=10\ in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7c7lvwrto85n1c3q0g1h57z9o3122o6n61.png)
The total area is
![A=A_1+A_2+A_3=28+21+10=59\ in^2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/pnljb3s3h1ibmu6j02ty9z8ym25fetg36i.png)