Question

A sample of gas occupies a volume of 57.9 L at 300K. Use Charles’s Law to calculate the volume (L) when the temperature is 264K. Show the calculation.

Answer 1

When the temperature lowers to 264K the volume lowers to 50.95 L

Step-by-step explanation:

Step 1: Data given

The initial volume of a gas = 57.9 L

The initial temperature = 300 K

The temperature lowers to 264 K

Step 2: Charles's law

V1 / T1 = V2 / T2

⇒ with V1 = the initial volume of the gas = 57.9 L

⇒ with T1 = the initial temperature = 300K

⇒ with V2 the new volume = TO BE DETERMINED

⇒ with T2 = the final temperature = 264K

57.9L /300K = V2 / 264K

V2 = (57.9*264)/300

V2 = 50.95 L

When the temperature lowers to 264K the volume lowers to 50.95 L