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You lower a 2.8 kg solid gold statue into a container of water and measure the volume of displaced water. What volume will verify that it is pure gold if the density of gold is 19.3 g/cm3

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Answer:

V = 145 cm³

Step-by-step explanation:

given,

mass of the solid = 2.8 Kg

= 2800 g

density of the gold = 19.3 g/cm³

volume of the water displaced = ?

volume of water displaced is equal to the volume of statue.

Volume of statue = ?


Volume = (mass)/(density)


Volume = (2.8* 1000)/(19.3)

V = 145 cm³

volume of the water displaced will be equal to 145 cm³

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