Question

Rewrite the equation by completing the square.
4x^2 + 28x + 49=0

Answer 1

g(x)=4(x-7/2)^2+0

Explanation:

Got it on Khan academy DO NOT USE THE ANSWER ABOVE INCORRECT

Answer 2

`4(x+3.5)^(2)=0`

Explanation:

we have

`4x^(2)+28x+49=0`

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

`(4x^(2)+28x)=-49`

step 2

Factor the leading coefficient

`4(x^(2)+7x)=-49`

step 3

Complete the square. Remember to balance the equation by adding the same constants to each side

`4(x^(2)+7x+3.5^2)=-49+(3.5^2)(4)`

`4(x^(2)+7x+12.25)=0`

step 4

Rewrite as perfect squares

`4(x+3.5)^(2)=0`