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X + 2y + 3z = 9 x - y - z = - 1 2x + y - 2z = 4

User Vpoltave
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1 Answer

6 votes

Answer:

The values for the given equations are x=2,y=2 and z=1

Explanation:

Given equations are
x+2y+3z=9\hfill (1)


x-y-z=-1\hfill (2)


2x+y-2z=4\hfill (3)

Now solving the given equations

Subtracting equations (1) and (2) we get


x+2y+3z=9


x-y-z=-1

________________


3y+4z=10\hfill (4)

Multiplying the equation (2) into 2 we get


2x-2y-2z=-2\hfill (5)

Now subtracting equations (5) and (3) we get


2x-2y-2z=-2


2x+y-2z=4

________________

-3y=-6


y=(6)/(3)

Therefore y=2

Substitute y=2 in equation (4) we get

3y+4z=10

3(2)+4z=10

4z=10-6


z=(4)/(4)

Therefore z=1

Substitute y=2 and z=1 in equation (1) we get

x+2(2)+3(1)=9

x=9-3-4

Therefore x=2

Therefore the values for the given equations are x=2,y=2 and z=1

User Mcsilvio
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