Answer:
33.83 g
Step-by-step explanation:
Data given:
Amount of Oxygen = 14.5 grams
Grams of Iron (Fe) = ?
Solution:
To solve this problem first we will look for the reaction that iron react with oxygen
Reaction:
4Fe + 3O₂ --------> 2Fe₂O₃
Now if we look at the reaction
4Fe + 3O₂ --------> 2Fe₂O₃
4 mol 3 mol
Now convert moles to mass
Then
Molar mass of iron = 56 g/mol
Molar mass of O₂ = 2(16) = 32 g/mol
So,
4Fe + 3O₂ ------------> 2Fe₂O₃
4 mol (56 g/mol) 3 mol (32 g/mol)
224 g 96 g
So if we look at the reaction; 224 g of iron (Fe) react with 96 g of oxygen (O₂) in a this reaction, then how many grams of iron (Fe) will react with 14.5 grmoles of iron (Fe)
For this apply unity formula
224 g of iron (Fe) ≅ 96 g of oxygen (O₂)
X of iron (Fe) ≅ 14.5 g of oxygen (O₂)
By Doing cross multiplication
X g of iron (Fe) = 224 g x 14.5 g / 96 g
X g of iron (Fe) = 33.83 g
33.83 g of iron (Fe) will react with 14.5 g of oxygen (O₂)