179k views
1 vote
How many moles of sodium atoms are contained in 3.5 moles of sodium sulfide

2 Answers

5 votes

Final answer:

In 3.5 moles of sodium sulfide (Na₂S), there are 7 moles of sodium atoms because each molecule of sodium sulfide contains two sodium atoms.

Step-by-step explanation:

To calculate the number of moles of sodium atoms contained in 3.5 moles of sodium sulfide (Na₂S), we need to consider the chemical formula of the compound. Sodium sulfide is made up of two sodium atoms (Na) for every sulfide ion (S²⁻). Therefore, each mole of Na₂S will contain 2 moles of sodium atoms.

Using this stoichiometric relationship, the calculation for the number of moles of sodium atoms in 3.5 moles of sodium sulfide is as follows:

  • Number of moles of Na in Na₂S = Number of moles of Na₂S * Number of Na atoms per molecule of Na₂S
  • Number of moles of Na = 3.5 moles * 2 moles of Na/mole of Na₂S
  • Number of moles of Na = 7 moles
  • Therefore, there are 7 moles of sodium atoms in 3.5 moles of sodium sulfide.
User Swetabh Suman
by
8.3k points
3 votes

Answer:

7 moles

Step-by-step explanation:

The molecular formula of sodium sulfide is Na_2S

One molecule of Sodium sulfide has 2 atoms of sodium and one atom of sulfur

1 mole of Sodium sulfide has 2 moles of sodium and one mole of sulfur

so 3.5 moles of sodium sulfide will have 2× 3.5 moles of sodium atoms

i.e 2×3.5= 7 moles of sodium atom

User Marty Lamb
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.