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The area of an equilateral triangle is given by A =3^1/2/4s^2. Find the length of the side s of an equilateral triangle with an area of 12^1/2 square inches.

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Answer:

The length of the side of an equilateral traingle
s=2√(2) inches

Explanation:

Given that the area of an equilateral triangle is given by


A=3^(1)/(2)s^2

It can be written as


a=(√(3))/(4) s^2 Square inches (1)

To find the length of the side s os an equilateral triangle

Given that area of an equilateral triangle is
12^(1)/(2) square inches

It can be written as


A=12^(1)/(2)


A=√(12) square inches

It can be written as


A=12^(1)/(2)


A=√(12) square inches (2)

Now comparing equations (1) and (2) we get


(√(3))/(4)s^2=√(12)


(√(3))/(4)s^2=√(4* 3)

Dividing by
(√(3))/(4) on both sides we get


((√(3))/(4)s^2)/((√(3))/(4))=(2√(3))/((√(3))/(4))


(√(3))/(4)s^2*(4)/(√(3))=2√(3)*(4)/(√(3))


s^2=8


s=√(8)

Therefore
s=2√(2) inches

Therefore the length of the side of an equilateral traingle
s=2√(2) inches

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