Question

rectangle ABCD is graphed in the cordinate plane. The following are the verticies of the rectangle; A(-6,-4),B(-4,-4),C(-4,-2), and D (-6,-2). what is the perimiter

Answer 1

Therefore Perimeter of Rectangle ABCD is 4 units

Step-by-step explanation:

Given:

ABCD is a Rectangle.

A(-6,-4),

B(-4,-4),

C(-4,-2), and

D (-6,-2).

To Find :

Perimeter of Rectangle = ?

Solution:

Answer 2

Therefore Perimeter of Rectangle ABCD is 4 units

Explanation:

Given:

ABCD is a Rectangle.

A(-6,-4),

B(-4,-4),

C(-4,-2), and

D (-6,-2).

To Find :

Perimeter of Rectangle = ?

Solution:

Perimeter of Rectangle is given as

`\textrm{Perimeter of Rectangle}=2(Length+Width)`

Length = AB

Width = BC

Now By Distance Formula we have'

`l(AB) = \sqrt{((x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2) )}`

Substituting the values we get

`l(AB) = \sqrt{((-4-(-6))^(2)+(-4-(-4))^(2) )}`

`l(AB) = \sqrt{((2)^(2)+(0)^(2) )}=2\ unit`

Similarly

`l(BC) = \sqrt{((-4-(-4))^(2)+(-2-(-4))^(2) )}`

`l(BC) = \sqrt{((0)^(2)+(2)^(2) )}=2\ unit`

Therefore now

Length = AB = 2 unit

Width = BC = 2 unit

Substituting the values in Perimeter we get

`\textrm{Perimeter of Rectangle}=2(2+2)=2(4)=8\ unit`

Therefore Perimeter of Rectangle ABCD is 4 units