Question

The electric dipole moment of a water molecule (H2O) is 6.13×10−30 C⋅m. You place a water molecule in a uniform electric field of magnitude 3.00×105N/C, with the dipole moment vector at an angle of 50.0∘ from the direction of the field. Calculate the magnitude of the torque on the water molecule.

Answer 1

The torque on the water molecule is 1.41×10^-24 Nm. The torque on a dipole is given by the formula

T = pE×Sin(phi)

Where p = the electric dipole moment

E = electric field

Phi = the angle between the electric field and the electric dipole moment.

Step-by-step explanation:

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