Question

Starting at 1.0 m/s, a cheetah runs with a constant acceleration for 4.8 s reaching a speed of 28 m/s. What is the acceleration of this cheetah? a. 6.5 m/s^2 b. 7.2 m/s^2 c. 5.6 m/s^2 d. 5.8 m/s^2 e. 7.7 m/s^2

Answer 1

c.
`5.6m/s^2`

Step-by-step explanation:

Initial velocity of cheetah,u=1 m/s

Time taken by cheetah =4.8 s

Final velocity of cheetah,v=28 m/s

We have to find the acceleration of this cheetah.

We know that

Acceleration,
`a=(v-u)/(t)`

Where v=Final velocity of object

u=Initial velocity of object

t=Time taken by object

Using the formula

Then, we get

Acceleration, a=
`(28-1)/(4.8)=(27)/(4.8) m/s^2`

Acceleration=
`a=5.6 m/s^2`

Hence, the acceleration of cheetah=
`5.6m/s^2`