107k views
2 votes
Cryolite, Na3AlF6(s), an ore used in the production of aluminum, can be synthesized using aluminum oxide. Balance the equation for the synthesis of cryolite.

Equation: Al2O3(s) + NaOH(l) + HF(g) --------> Na3AlF6 + H2O(g)
1. If 15.8 kg of Al2O3(s), 55.4 kg of NaOH(l), and 55.4 kg of HF(g) react completely, how many kilograms of cryolite will be produced?

1 Answer

5 votes

Answer: The mass of cryolite produced is 65.06 kg

Step-by-step explanation:

To calculate the number of moles, we use the equation:


\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} .....(1)

  • For aluminium oxide:

Given mass of aluminium oxide = 15.8 kg = 15800 g (Conversion factor: 1 kg = 1000 g)

Molar mass of aluminium oxide = 102 g/mol

Putting values in equation 1, we get:


\text{Moles of aluminium oxide}=(15800g)/(102g/mol)=154.9mol

For the given chemical reaction:


Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O(g)

As all the reactants are getting completely utilized. So, the amount of product can be determined by any 1 of the reactant.

By Stoichiometry of the reaction:

1 mole of aluminium oxide produces 2 moles of cryolite

So, 154.9 moles of aluminium oxide produces =
(2)/(1)* 154.9=309.8mol of cryolite

Now, calculating the mass of cryolite by using equation 1, we get:

Moles of cryolite = 309.8 moles

Molar mass of cryolite = 210 g/mol

Putting values in equation 1, we get:


309.8mol=\frac{\text{Mass of cryolite}}{210g/mol}\\\\\text{Mass of cryolite}=(309.8mol* 210g/mol)=65058g=65.06kg

Hence, the mass of cryolite produced is 65.06 kg

User Zeodtr
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.