Question

In a recent poll of 1100 randomly selected home delivery truck drivers, 26% said they had encountered an aggressive dog on the job at least once. What is the standard error for the estimate of the proportion of all home delivery truck drivers who have encountered an aggressive dog on the job at least once? Round to the nearest ten-thousandth a) 0.0141 b) 0.0002 c) 0.1322 d) 0.0132

Answer 1

d) 0.0132

Explanation:

In a sample of size n, with proportion p, the standard error of the proportion is:

`SE_(p) = \sqrt{(p(1-p))/(n)}`

In this problem, we have that:

`p = 0.26, n = 1100`

So

`SE_(p) = \sqrt{(p(1-p))/(n)} = \sqrt{(0.26*0.74)/(1100)} = 0.0132`

So the correct answer is:

d) 0.0132